最高のコレクション 1+tan^2x/1+cot^2x=tan^2x 235744-1+tan^2x/1+cot^2 x=(1-tanx/1-cotx)^2
tan^2x (1tan^2x)/(1cot^2x) 1) First, notice that both the numerator and denominator are Pythagorean Identities Proceed to change them sec^2x/csc^2x 2) Turn into sine and cosine Then multiply (1/cos^2x)/(1/sin^2x) >Tan B=3/4 then findTan^2xcot^2x=tan^2x1/tan^2x =(sinx)^4(cosx)^4/(sinxcosx)^2 ={(sinx)^2(cosx)^2^22(sinxcosx)^2}/(sinxcosx)^2 =12(sinxcosx)^2/(sinxcosx)^2 =411/2(sin2x)^2 Solved Simplify Sin 2x Cot 2x 1 Oa B Tan 2x Cos X Chegg Com 1+tan^2x/1+cot^2 x=(1-tanx/1-cotx)^2